-16x^2+216x+6=0

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Solution for -16x^2+216x+6=0 equation:



-16x^2+216x+6=0
a = -16; b = 216; c = +6;
Δ = b2-4ac
Δ = 2162-4·(-16)·6
Δ = 47040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{47040}=\sqrt{3136*15}=\sqrt{3136}*\sqrt{15}=56\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(216)-56\sqrt{15}}{2*-16}=\frac{-216-56\sqrt{15}}{-32} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(216)+56\sqrt{15}}{2*-16}=\frac{-216+56\sqrt{15}}{-32} $

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